0.4=5x^2

Solution for 0.4=5x^2 equation:

0.4=5x^2

We move all terms to the left:

0.4-(5x^2)=0

a = -5; b = 0; c = +0.4;
Δ = b2-4ac
Δ = 02-4·(-5)·0.4
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2}}{2*-5}=\frac{0-2\sqrt{2}}{-10}
=-\frac{2\sqrt{2}}{-10}
=-\frac{\sqrt{2}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2}}{2*-5}=\frac{0+2\sqrt{2}}{-10}
=\frac{2\sqrt{2}}{-10}
=\frac{\sqrt{2}}{-5}
$